A box contains 3 red, 5 blue and 2 green balls. Three balls are drawn one after another without replacement.
Make a three-level tree. Multiply the probabilities on the Red → Blue → Green path.
This question is GCSE Higher because it uses a three-stage tree diagram. With each draw the total number of balls changes, and the number of each colour can change depending on what was drawn. This increases the chance of errors, so a tree diagram is the safest way to organise the work.
The balls are drawn without replacement. That means:
For Higher tier, you should show enough branches to reflect the full process. A clear approach is:
This keeps the diagram readable while still being a genuine three-level tree.
Once the tree is labelled, the probability of a sequence is found by multiplying along the path. For example:
P(R then B then G) = P(R) × P(B|R) × P(G|R and B)
A bag contains 2 red, 4 blue and 3 green balls. Three balls are drawn without replacement. Find the probability of drawing Blue then Green then Red.
Write the totals under each stage of the tree (10 → 9 → 8). This simple habit prevents most errors in Higher tree-diagram questions.
Study tip: For any “A then B then C” question without replacement, think: three branches, three fractions, multiply along one path.
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