This Higher-tier question applies standard form to compare data transfer speeds in computing.
When dividing numbers in standard form, subtract the powers and divide the coefficients. Rewrite your final coefficient between 1 and 10.
Standard form is widely used in computing and digital technology to describe very large and very small quantities, such as data rates, frequencies, and storage capacities. Comparing these quantities often requires forming ratios. Using standard form allows engineers and analysts to express and compare magnitudes without handling long strings of zeros.
A ratio compares how many times one value contains another. In standard form, division follows the law of indices:
\[ \dfrac{a_1 \times 10^{n_1}}{a_2 \times 10^{n_2}} = \left( \dfrac{a_1}{a_2} \right) \times 10^{n_1 - n_2}. \]
Dividing numbers in standard form therefore involves two steps: dividing the coefficients and subtracting the exponents. The result should always be written so that the coefficient lies between 1 and 10 to maintain correct standard form.
Suppose an old USB 2.0 port transfers data at \( 4.8 \times 10^8 \text{ bits/s} \), while a modern fibre connection reaches \( 9.6 \times 10^{11} \text{ bits/s} \). To find how many times faster the fibre connection is:
\[ \dfrac{9.6 \times 10^{11}}{4.8 \times 10^8} = (2.0) \times 10^{3} = 2.0 \times 10^3. \]
This shows the fibre link is about 2000 times faster.
A computer with a memory of \( 3.2 \times 10^9 \text{ bytes} \) is compared with a smaller device holding \( 8.0 \times 10^7 \text{ bytes} \). The ratio is:
\[ \dfrac{3.2 \times 10^9}{8.0 \times 10^7} = 0.4 \times 10^{2} = 4.0 \times 10^1. \]
The computer has 40 times more memory.
In computing, standard form helps when expressing file sizes, bandwidths, and processor speeds that span multiple magnitudes. For instance, a processor operating at \( 3.6 \times 10^9 \text{ Hz} \) (3.6 GHz) compared to an older 486 processor at \( 6.0 \times 10^6 \text{ Hz} \) has a ratio of:
\[ \dfrac{3.6 \times 10^9}{6.0 \times 10^6} = 0.6 \times 10^{3} = 6.0 \times 10^2. \]
This shows the modern CPU is around 600 times faster.
Q1: Why subtract powers when dividing?
A: Because \( 10^a \div 10^b = 10^{a-b} \). The difference between the exponents shows how many factors of ten separate the values.
Q2: Can ratios in computing be less than one?
A: Yes. If the numerator is smaller, the result has a coefficient below 1, which you must adjust back into standard form.
Q3: Does the unit cancel out in ratios?
A: When both quantities share the same unit (e.g., bits per second), the ratio itself is dimensionless—it simply compares magnitudes.
Always perform ratio calculations carefully: divide coefficients separately from exponents. In computer science, this technique is vital for comparing speeds, storage, and signal strengths expressed in scientific notation. Showing clear steps ensures full marks in GCSE Higher exams involving standard form and powers of ten.