GCSE Maths Practice: polygons

Question 3 of 10

This question asks for the size of each interior angle of a regular nonagon.

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\( \begin{array}{l}\text{Find the size of each interior angle of a regular nonagon.}\end{array} \)

Choose one option:

Use formula (n-2) × 180° to find sum, then divide by number of sides.

To find each interior angle of a regular polygon, first calculate the sum of interior angles using (n-2) × 180°, where n is the number of sides. Then divide the sum by n. For a nonagon (9 sides), sum = (9-2) × 180 = 1260°. Each angle = 1260 ÷ 9 = 140°. Understanding this procedure helps solve polygon angle problems, ensures accurate diagram reasoning, and strengthens geometric skills in GCSE exams.