Find the vertex of a downward-opening parabola in vertex form.
\( \text{Where is the vertex of the parabola } y = -2(x + 1)^2 + 5? \)
Choose one option:
Read h and k from the formula, adjust for sign.
Vertex is \((h,k)\) in \(y = a(x-h)^2 + k\); adjust h for the sign inside the bracket.
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