Find the vertex of a quadratic function.
\( \text{Find the vertex of the quadratic function } y = -x^2 + 6x - 5. \)
Choose one option:
Compute x-coordinate from axis of symmetry, then find y-coordinate.
The vertex is \((x, y)\) found using \(x = -b/(2a)\) and substituting back into \(y = ax^2 + bx + c\).
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