This question illustrates conditional probability when only one type remains.
\( \begin{array}{l}\text{A box contains 6 red balls and 4 blue balls.} \\ \text{One ball is drawn at random.} \\ \text{What is the probability it is red, given that it is not blue?}\end{array} \)
Choose one option:
Check which items satisfy the condition; probability is 1 if only one type remains.
If the condition excludes all other types, probability for the remaining type is 1.
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