Surface Area of a Cone

\( S=\pi r\,\ell+\pi r^2 \)
Geometry GCSE

\( A cone has r = 3 cm and ℓ = 7 cm. Find the total surface area (in terms of π). \)

Tips: use ^ for powers, sqrt() for roots, and type pi for π.
Hint (H)
\( S = πrℓ + πr². \)

Explanation

Show / hide — toggle with X

Statement

The surface area of a cone is the sum of the curved (lateral) surface area and the base area:

\[ S = \pi r \ell + \pi r^2 \]

where \(r\) is the radius and \(\ell\) is the slant height of the cone.

Why it’s true

  • The curved surface of a cone unfolds into a sector of a circle with radius \(\ell\). Its area is \(\pi r \ell\).
  • The circular base has area \(\pi r^2\).
  • Adding them gives the total surface area.

Recipe (how to use it)

  1. Identify the radius \(r\) and slant height \(\ell\).
  2. Calculate the curved surface area using \(\pi r \ell\).
  3. Calculate the base area using \(\pi r^2\).
  4. Add the two areas to get the total surface area.

Spotting it

Look for words like “surface area of a cone”, “total surface area”, or a problem giving radius and slant height.

Common pairings

  • Volume of a cone \(\tfrac{1}{3}\pi r^2 h\).
  • Pythagoras’ theorem if slant height is not given (\(\ell = \sqrt{r^2 + h^2}\)).

Mini examples

  1. Given: \(r=3\), \(\ell=5\). Answer: \(S=\pi(3)(5)+\pi(3^2)=15\pi+9\pi=24\pi\).
  2. Given: \(r=7\), \(\ell=25\). Answer: \(S=\pi(7)(25)+\pi(49)=175\pi+49\pi=224\pi\).

Pitfalls

  • Confusing slant height with vertical height.
  • Forgetting to include the base area.
  • Mixing units (e.g. cm with m).

Exam strategy

  • Check whether the question asks for curved surface area only or total surface area.
  • Write down both terms clearly before adding.
  • Always square the radius only when calculating \(\pi r^2\).

Summary

The surface area of a cone is found with \(S = \pi r \ell + \pi r^2\). The first term is the curved surface, the second is the base area.

Worked examples

Show / hide (10) — toggle with E
  1. Find the surface area of a cone with radius 3 cm and slant height 5 cm (leave in terms of π).
    1. \( S = πrℓ + πr² \)
    2. \( S = π(3)(5) + π(3²) \)
    3. \( S = 15π + 9π = 24π \)
    Answer: 24π cm²
  2. \( Find the surface area of a cone with r=4 cm, ℓ=6 cm. \)
    1. \( S = πrℓ + πr² \)
    2. \( S = π(4)(6) + π(16) \)
    3. \( S = 24π + 16π = 40π \)
    Answer: 40π cm²
  3. \( Find the total surface area when r=7 cm, ℓ=25 cm. \)
    1. \( S = π(7)(25) + π(49) \)
    2. \( S = 175π + 49π = 224π \)
    Answer: 224π cm²
  4. \( A cone has r=10 cm, ℓ=15 cm. Find surface area. \)
    1. \( S = π(10)(15) + π(100) \)
    2. \( S = 150π + 100π = 250π \)
    Answer: 250π cm²
  5. \( Find the surface area for r=2 cm, ℓ=5 cm. \)
    1. \( S = π(2)(5) + π(4) \)
    2. \( S = 10π + 4π = 14π \)
    Answer: 14π cm²
  6. \( A cone has r=6 cm and vertical height h=8 cm. Find surface area. \)
    1. \( Find ℓ = √(r²+h²) = √(36+64)=√100=10 \)
    2. \( S = π(6)(10) + π(36) \)
    3. \( S = 60π + 36π = 96π \)
    Answer: 96π cm²
  7. \( Find surface area of a cone with r=9 cm, h=12 cm. \)
    1. \( ℓ=√(81+144)=√225=15 \)
    2. \( S=π(9)(15)+π(81) \)
    3. \( S=135π+81π=216π \)
    Answer: 216π cm²
  8. \( A cone with r=8 cm, ℓ=17 cm. Find surface area. \)
    1. \( S = π(8)(17) + π(64) \)
    2. \( S = 136π + 64π = 200π \)
    Answer: 200π cm²
  9. \( Find total surface area when r=5 cm, ℓ=13 cm. \)
    1. \( S=π(5)(13)+π(25) \)
    2. \( S=65π+25π=90π \)
    Answer: 90π cm²
  10. \( Find surface area of cone with r=12 cm, ℓ=20 cm. \)
    1. \( S=π(12)(20)+π(144) \)
    2. \( S=240π+144π=384π \)
    Answer: 384π cm²