Statement
For simple interest calculations:
\[
I = \frac{Prt}{100}, \quad A = P+I
\]
where \(P\) is the principal, \(r\) is the annual rate of interest (%), \(t\) is the time in years, \(I\) is interest, and \(A\) is the final amount.
Why it’s true
- Simple interest grows linearly — the same amount is added each year.
- For one year: interest = \(P \times r/100\).
- For \(t\) years: interest = \(P \times r/100 \times t\).
- Total = principal + interest.
Recipe (how to use it)
- Identify \(P\), \(r\), and \(t\).
- Calculate \(I=(Prt)/100\).
- Add to principal for total \(A=P+I\).
Spotting it
Look for problems with fixed yearly percentages, e.g. “£500 at 6% simple interest for 3 years”.
Common pairings
- Bank savings questions.
- Loans and repayments.
- Comparisons with compound interest.
Mini examples
- £500 at 6% for 3 years → \(I=(500×6×3)/100=90\), \(A=590\).
- £2000 at 4% for 5 years → \(I=(2000×4×5)/100=400\), \(A=2400\).
- £800 at 10% for 2 years → \(I=(800×10×2)/100=160\), \(A=960\).
Pitfalls
- Forgetting to divide by 100 when rate is a percentage.
- Using compound instead of simple interest formula.
- Confusing years with months (convert months into years).
Exam strategy
- Write down values of \(P,r,t\) before calculating.
- Always check if question asks for interest or total amount.
- If given monthly/quarterly, convert time into years correctly.
Summary
Simple interest: \(I=(Prt)/100\), \(A=P+I\). Interest increases in a straight line with time.