Triangle perimeter 30 scaled by 0.5. New perimeter?
Explanation
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Statement
When a 2D shape is scaled by a scale factor \(k\):
The perimeter is multiplied by \(k\): \(\; P' = kP\).
The area is multiplied by \(k^2\): \(\; A' = k^2A\).
Why it’s true
All side lengths scale directly with the scale factor \(k\), so the perimeter (sum of sides) scales by \(k\).
The area is proportional to the square of lengths (since area involves two dimensions), so the area scales by \(k^2\).
Recipe (how to use it)
Identify the scale factor \(k\).
To find new perimeter: multiply old perimeter by \(k\).
To find new area: multiply old area by \(k^2\).
Spotting it
This appears in enlargement problems, similarity questions, and exam questions about ratios of areas and perimeters.
Common pairings
Similar triangles, rectangles, or polygons.
Circle scaling (perimeter = circumference, area = πr²).
Maps, models, and real-life enlargements or reductions.
Mini examples
Given: A square has perimeter 40. Enlarged by scale factor 3. Answer: New perimeter = \(3 \times 40 = 120\).
Given: Rectangle has area 20. Enlarged by scale factor 4. Answer: New area = \(4^2 \times 20 = 320\).
Pitfalls
Forgetting to square the scale factor for area.
Confusing perimeter and area scaling rules.
Mixing up ratios of sides with ratios of areas.
Exam strategy
Always check whether the question is about perimeter or area.
Write down \(P' = kP\) and \(A' = k^2A\) explicitly to avoid mistakes.
If a question gives you ratios of areas, take the square root to find the scale factor.
Summary
Under enlargement by a scale factor \(k\), perimeters scale by \(k\) and areas scale by \(k^2\). This is essential in similarity and enlargement problems.
Worked examples
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Square with perimeter 40 enlarged by scale factor 3. Find new perimeter.
\( P'=kP \)
\( 3*40=120 \)
Answer:
120
Rectangle with area 20 enlarged by scale factor 4. Find new area.
\( A'=k^2A \)
\( 4^2*20=320 \)
Answer:
320
\( Circle radius 5 scaled by 2. Find new circumference if old=31.4. \)
\( P'=kP \)
\( 2*31.4=62.8 \)
Answer:
62.8
Circle area 78.5 enlarged by factor 2. Find new area.
\( A'=k^2A \)
\( 4*78.5=314 \)
Answer:
314
Triangle perimeter 24 scaled by 0.5. Find new perimeter.
\( P'=0.5*24=12 \)
Answer:
12
Rectangle area 50 enlarged by 1.5. Find new area.
\( A'=1.5^2*50 \)
\( 2.25*50=112.5 \)
Answer:
112.5
Polygon perimeter 80 scaled by 1.25. Find new perimeter.
\( P'=1.25*80=100 \)
Answer:
100
Square area 36 enlarged by 3. Find new area.
\( A'=3^2*36=9*36=324 \)
Answer:
324
Shape perimeter 60 reduced by scale factor 0.2. Find new perimeter.
\( P'=0.2*60=12 \)
Answer:
12
Area of shape 100 reduced by scale factor 0.5. Find new area.