Inverse Proportion to a Power

\( y\propto \tfrac{1}{x^{k}}\;\Rightarrow\; y=\tfrac{k}{x^{k}} \)
Proportion GCSE

\( y \propto 1/x^4. If y=625 when x=1, find y when x=5. \)

Tips: use ^ for powers, sqrt() for roots, and type pi for π.
Hint (H)
y×x⁴ is constant.

Explanation

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Statement

A quantity is in inverse proportion to a power if it decreases as another variable increases, with the relationship involving a power of the variable. Mathematically:

\[ y \propto \tfrac{1}{x^k} \quad \Rightarrow \quad y = \tfrac{k}{x^n} \]

Here, \(n\) is the power of \(x\), and \(k\) is a constant of proportionality.

Why it’s true

  • When one variable decreases as a power of another variable increases, their product involving that power remains constant.
  • For example, in physics, gravitational force \(F\) is inversely proportional to the square of distance: \(F \propto \tfrac{1}{r^2}\).
  • This reflects the fact that the influence spreads over an area (or volume), which grows as a power of distance.

Recipe (how to use it)

  1. Write the formula as \(y = \tfrac{k}{x^n}\).
  2. Use known values of \(x\) and \(y\) to find the constant \(k\).
  3. Substitute into the equation to find unknown values of \(y\) or \(x\).
  4. Remember: \(y \times x^n = k\) is constant.

Spotting it

Problems often say “\(y\) varies inversely with the square (or cube, etc.) of \(x\).” This signals inverse proportion to a power.

Common pairings

  • Physics: Inverse-square laws (gravity, light intensity, electrostatics).
  • Mathematics: Hyperbolic and rational functions.
  • Engineering: Sound intensity and radiation spread.

Mini examples

  1. Given: \(y\) varies inversely with \(x^2\). If \(y=20\) when \(x=2\), find \(y\) when \(x=5\). Solution: \(k=yx^2=20×2^2=80.\) For \(x=5\), \(y=80/25=3.2.\)
  2. Given: Intensity of light \(I \propto 1/d^2\). If intensity is 100 at distance 2 m, what is it at 10 m? Solution: \(k=100×2^2=400.\) At 10 m, \(I=400/100=4.\)

Pitfalls

  • Forgetting the power: Always check whether it’s inverse square, cube, etc.
  • Confusing with simple inverse proportion: That’s only \(y=k/x\) (power of 1).
  • Arithmetic errors: Be careful with squaring/cubing before dividing.

Exam strategy

  • Write \(y \times x^n = k\) at the start.
  • Use the given pair of values to calculate \(k\).
  • Substitute into the formula to find the unknown.
  • Double-check powers and units if it’s a physics context.

Summary

Inverse proportion to a power means one quantity decreases as the power of another increases. Formula: \(y=k/x^n\). Typical examples include inverse-square laws in physics. Remember: always multiply \(y\) by \(x^n\) to get the constant.

Worked examples

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  1. \( y ∝ 1/x². If y=20 when x=2, find y when x=5. \)
    1. \( k=yx²=20×2²=80. \)
    2. \( For x=5, y=80/25=3.2. \)
    Answer: 3.2
  2. \( y varies inversely with x². If y=18 when x=3, find y when x=6. \)
    1. \( k=18×3²=162. \)
    2. \( For x=6, y=162/36=4.5. \)
    Answer: 4.5
  3. \( y ∝ 1/x³. If y=40 when x=2, find y when x=4. \)
    1. \( k=40×2³=40×8=320. \)
    2. \( For x=4, y=320/64=5. \)
    Answer: 5
  4. \( y varies inversely with x². If y=10 when x=1, find y when x=10. \)
    1. \( k=10×1²=10. \)
    2. \( For x=10, y=10/100=0.1. \)
    Answer: 0.1
  5. \( y ∝ 1/x². If y=50 when x=2, find y when x=8. \)
    1. \( k=50×2²=200. \)
    2. \( For x=8, y=200/64=3.125. \)
    Answer: 3.125
  6. \( y ∝ 1/x³. If y=81 when x=1, find y when x=3. \)
    1. \( k=81×1³=81. \)
    2. \( For x=3, y=81/27=3. \)
    Answer: 3
  7. \( y ∝ 1/x². If y=72 when x=2, find y when x=12. \)
    1. \( k=72×2²=288. \)
    2. \( For x=12, y=288/144=2. \)
    Answer: 2
  8. \( In physics, F ∝ 1/r². If F=100 when r=5, find F when r=20. \)
    1. \( k=100×5²=2500. \)
    2. \( For r=20, F=2500/400=6.25. \)
    Answer: 6.25
  9. \( y ∝ 1/x⁴. If y=256 when x=1, find y when x=2. \)
    1. \( k=256×1⁴=256. \)
    2. \( For x=2, y=256/16=16. \)
    Answer: 16
  10. \( y ∝ 1/x². If y=9 when x=1, find y when x=3. \)
    1. \( k=9×1²=9. \)
    2. \( For x=3, y=9/9=1. \)
    Answer: 1