In other words, speed equals the change in distance divided by the change in time.
Why it’s true
A distance–time graph plots distance travelled against time.
The steepness (gradient) of the graph tells us how fast distance increases with time.
The formula for a gradient is "rise over run", which here is "distance over time".
Therefore, the gradient of the line equals the speed.
Recipe (how to use it)
Pick two points on the straight-line section of the distance–time graph.
Find the change in distance (\(\Delta d\)) and change in time (\(\Delta t\)).
Divide distance by time: \( \text{Speed} = \Delta d / \Delta t \).
If the graph has curves, draw a tangent at the point and find its gradient to get instantaneous speed.
Spotting it
This formula applies whenever you are interpreting a distance–time graph, whether for constant speed (straight line) or variable speed (curved line).
Common pairings
Uniform motion problems (straight-line graph).
Acceleration problems (where gradient changes).
Comparing speeds of two objects by comparing gradients.
Mini examples
Given: In 2 hours, a car travels 100 km. On the graph, line joins (0,0) to (2,100). Answer: Gradient = 100/2 = 50 km/h.
Given: A train covers 60 km in 1.5 h. Answer: Gradient = 60/1.5 = 40 km/h.
Pitfalls
Mixing up axes: time should always be on the horizontal axis.
Using total distance instead of change in distance.
Forgetting to keep units consistent (minutes vs hours).
Exam strategy
Clearly label the two points used to calculate the gradient.
Show working with rise/run to avoid errors.
If graph is curved, draw tangent carefully.
Summary
The gradient of a distance–time graph gives the speed. A steeper line means a higher speed. This method works for both constant and changing speeds, making it a powerful tool in interpreting motion graphs.
Worked examples
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On a distance–time graph, a line goes from (0,0) to (2,80). Find the speed.
\( Δdistance = 80, Δtime = 2 \)
\( Speed = 80/2 = 40 \)
Answer:
40 units/hour
A graph shows a journey from (0,0) to (4,200). What is the speed?
\( Δdistance = 200, Δtime = 4 \)
\( Speed = 200/4 = 50 \)
Answer:
50 units/hour
From (1,40) to (3,100), find the speed.
\( Δdistance = 100-40 = 60, Δtime = 3-1 = 2 \)
\( Speed = 60/2 = 30 \)
Answer:
30 units/hour
A straight-line section goes from (0,0) to (5,250). Find the speed.
\( Δdistance = 250, Δtime = 5 \)
\( Speed = 250/5 = 50 \)
Answer:
50 units/hour
On a graph, line goes from (2,60) to (6,180). Find speed.
\( Δdistance = 180-60=120, Δtime = 6-2=4 \)
\( Speed = 120/4 = 30 \)
Answer:
30 units/hour
Between (0,0) and (1,45), what is the speed?
\( Δdistance = 45, Δtime = 1 \)
\( Speed = 45/1 = 45 \)
Answer:
45 units/hour
Find the speed from (3,90) to (7,250).
\( Δdistance = 250-90=160, Δtime = 7-3=4 \)
\( Speed = 160/4 = 40 \)
Answer:
40 units/hour
From (2,50) to (5,170), what is the speed?
\( Δdistance = 170-50=120, Δtime = 3 \)
\( Speed = 120/3=40 \)
Answer:
40 units/hour
Line from (4,120) to (10,300). Find speed.
\( Δdistance = 300-120=180, Δtime = 6 \)
\( Speed = 180/6=30 \)
Answer:
30 units/hour
If a graph passes through (0,0) and (8,400), what is the speed?