Distance–Time Graph (Speed)

\( \text{Speed}=\text{gradient} = \frac{\Delta\text{distance}}{\Delta\text{time}} \)
Measures GCSE

If a graph passes through (0,0) and (7,350), what is the speed?

Hint (H)
Divide distance by time

Explanation

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Statement

On a distance–time graph, the speed of an object is represented by the gradient (slope) of the line. The formula is:

\[ \text{Speed} = \text{gradient} = \frac{\Delta \text{distance}}{\Delta \text{time}} \]

In other words, speed equals the change in distance divided by the change in time.

Why it’s true

  • A distance–time graph plots distance travelled against time.
  • The steepness (gradient) of the graph tells us how fast distance increases with time.
  • The formula for a gradient is "rise over run", which here is "distance over time".
  • Therefore, the gradient of the line equals the speed.

Recipe (how to use it)

  1. Pick two points on the straight-line section of the distance–time graph.
  2. Find the change in distance (\(\Delta d\)) and change in time (\(\Delta t\)).
  3. Divide distance by time: \( \text{Speed} = \Delta d / \Delta t \).
  4. If the graph has curves, draw a tangent at the point and find its gradient to get instantaneous speed.

Spotting it

This formula applies whenever you are interpreting a distance–time graph, whether for constant speed (straight line) or variable speed (curved line).

Common pairings

  • Uniform motion problems (straight-line graph).
  • Acceleration problems (where gradient changes).
  • Comparing speeds of two objects by comparing gradients.

Mini examples

  1. Given: In 2 hours, a car travels 100 km. On the graph, line joins (0,0) to (2,100). Answer: Gradient = 100/2 = 50 km/h.
  2. Given: A train covers 60 km in 1.5 h. Answer: Gradient = 60/1.5 = 40 km/h.

Pitfalls

  • Mixing up axes: time should always be on the horizontal axis.
  • Using total distance instead of change in distance.
  • Forgetting to keep units consistent (minutes vs hours).

Exam strategy

  • Clearly label the two points used to calculate the gradient.
  • Show working with rise/run to avoid errors.
  • If graph is curved, draw tangent carefully.

Summary

The gradient of a distance–time graph gives the speed. A steeper line means a higher speed. This method works for both constant and changing speeds, making it a powerful tool in interpreting motion graphs.

Worked examples

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  1. On a distance–time graph, a line goes from (0,0) to (2,80). Find the speed.
    1. \( Δdistance = 80, Δtime = 2 \)
    2. \( Speed = 80/2 = 40 \)
    Answer: 40 units/hour
  2. A graph shows a journey from (0,0) to (4,200). What is the speed?
    1. \( Δdistance = 200, Δtime = 4 \)
    2. \( Speed = 200/4 = 50 \)
    Answer: 50 units/hour
  3. From (1,40) to (3,100), find the speed.
    1. \( Δdistance = 100-40 = 60, Δtime = 3-1 = 2 \)
    2. \( Speed = 60/2 = 30 \)
    Answer: 30 units/hour
  4. A straight-line section goes from (0,0) to (5,250). Find the speed.
    1. \( Δdistance = 250, Δtime = 5 \)
    2. \( Speed = 250/5 = 50 \)
    Answer: 50 units/hour
  5. On a graph, line goes from (2,60) to (6,180). Find speed.
    1. \( Δdistance = 180-60=120, Δtime = 6-2=4 \)
    2. \( Speed = 120/4 = 30 \)
    Answer: 30 units/hour
  6. Between (0,0) and (1,45), what is the speed?
    1. \( Δdistance = 45, Δtime = 1 \)
    2. \( Speed = 45/1 = 45 \)
    Answer: 45 units/hour
  7. Find the speed from (3,90) to (7,250).
    1. \( Δdistance = 250-90=160, Δtime = 7-3=4 \)
    2. \( Speed = 160/4 = 40 \)
    Answer: 40 units/hour
  8. From (2,50) to (5,170), what is the speed?
    1. \( Δdistance = 170-50=120, Δtime = 3 \)
    2. \( Speed = 120/3=40 \)
    Answer: 40 units/hour
  9. Line from (4,120) to (10,300). Find speed.
    1. \( Δdistance = 300-120=180, Δtime = 6 \)
    2. \( Speed = 180/6=30 \)
    Answer: 30 units/hour
  10. If a graph passes through (0,0) and (8,400), what is the speed?
    1. \( Δdistance = 400, Δtime = 8 \)
    2. \( Speed = 400/8 = 50 \)
    Answer: 50 units/hour