Statement
Sometimes a variable is directly proportional not just to another variable, but to a power of that variable. In such cases we write:
\[ y \propto x^k \quad \Rightarrow \quad y = kx^k \]
Here, \(k\) is a constant of proportionality, and the exponent \(k\) tells us how the variable grows in relation to \(x\).
Why it’s true
- Direct proportion to a power means when \(x\) changes, \(y\) changes by a fixed multiple of \(x^k\).
- If \(k = 1\), this reduces to simple direct proportion.
- If \(k = 2\), then doubling \(x\) makes \(y\) increase by a factor of \(2^2 = 4\).
- Similarly, if \(k = 3\), doubling \(x\) makes \(y\) increase by \(2^3 = 8\).
Recipe (how to use it)
- Write \( y = kx^k \).
- Use a known pair of values of \(x\) and \(y\) to calculate \(k\).
- Use the equation to calculate other values of \(y\) when \(x\) changes.
Spotting it
Look for key phrases such as “\(y\) is proportional to the square of \(x\)” (\(k = 2\)), “\(y\) is proportional to the cube of \(x\)” (\(k = 3\)), or “\(y\) is proportional to the square root of \(x\)” (\(k = \tfrac{1}{2}\)).
Common pairings
- Area of a circle \(A \propto r^2\).
- Volume of a sphere \(V \propto r^3\).
- Time period of a pendulum \(T \propto \sqrt{L}\).
- Energy in physics problems, often proportional to square of speed or current.
Mini examples
- Given: \(y \propto x^2\), and \(y = 18\) when \(x = 3\). Find: the formula. Answer: \(18 = k \times 3^2 \Rightarrow k = 2\). So \(y = 2x^2\).
- Given: \(y \propto \sqrt{x}\), and \(y = 10\) when \(x = 25\). Find: \(k\). Answer: \(\sqrt{25} = 5\), so \(10 = k \times 5 \Rightarrow k = 2\). So \(y = 2\sqrt{x}\).
Pitfalls
- Forgetting that the power can be a fraction (square root, cube root).
- Mixing up direct proportion with inverse proportion (\(y \propto 1/x^k\)).
- Failing to compute powers correctly (e.g., squaring vs doubling).
Exam strategy
- Identify the correct power relationship from the wording.
- Always find \(k\) using given values before substitution.
- Check whether the answer should be left exact (e.g., surd form) or as a decimal.
Summary
Direct proportion to a power generalises the idea of proportionality. Instead of \(y\) being proportional to \(x\), it is proportional to \(x^k\). This appears in many real-world situations, from geometry (areas and volumes) to science (laws involving squares and roots). Recognising the correct power is the key step in solving such problems.