If more workers are used to do a job, what happens to the time taken?
Inverse Proportion
Inverse proportion describes a relationship where one quantity increases while the other decreases. It is the opposite of direct proportion and is based on ideas from ratio, with relationships often written in the form y = k/x.
Overview
Two quantities are in inverse proportion when one increases and the other decreases so that their product remains constant.
\( xy = k \)
Inverse proportion often appears in problems involving time, speed, workers, pipes, area and pressure.
What you should understand after this topic
- Understand what inverse proportion means
- Understand how inverse proportion differs from direct proportion
- Use y = k/x to solve problems
- Use xy = k to solve problems
- Solve missing-value problems involving inverse proportion
Key Definitions
Inverse Proportion
When one quantity increases while the other decreases so that the product stays constant.
Inverse Proportional To
\( y \propto \frac{1}{x} \)
Constant of Proportionality
The fixed value \( k \) in \( y = \frac{k}{x} \) or \( xy = k \).
Product
The result of multiplying two values together.
Reciprocal Relationship
One quantity is proportional to the reciprocal of the other.
Inverse Graph Shape
The graph is a curve, not a straight line.
Key Rules
Multiply to find the constant
\( k = xy \)
Use inverse formula
\( y = \frac{k}{x} \)
One goes up, the other goes down
That is the key pattern.
Graph is not a straight line
Inverse proportion makes a curve.
Quick Recognition
Words
“is inversely proportional to”
Equation
\( y = \frac{12}{x} \)
Product check
If \( xy \) stays constant, it is inverse proportion.
Graph pattern
A decreasing curve, not a straight line.
How to Solve
Step 1: Recognise inverse proportion
In inverse proportion, as one value increases, the other decreases so that their product stays constant. It is useful to compare this with direct proportion.
Step 2: Write the equation
Convert the proportional relationship into an equation.
Step 3: Find the constant \(k\)
Use given values to calculate \(k\).
Step 4: Use the equation
Substitute new values into the equation.
Step 5: Graph of inverse proportion
The graph is a curve that gets closer to the axes but never touches them.
Key idea
The graph is not a straight line and has two branches.
Step 6: How to recognise inverse proportion
From words
Look for 'inversely proportional'.
From a table
Check if \( xy \) is constant.
From an equation
Looks like \( y = \frac{k}{x} \).
From context
More workers → less time, higher speed → less time.
Step 7: Exam method summary
- Recognise inverse proportion.
- Write \( y = \frac{k}{x} \).
- Find \(k\) using known values.
- Substitute to find the answer.
Example Questions
Edexcel
Exam-style questions inspired by Edexcel GCSE Mathematics, focusing on recognising and solving problems involving inverse proportion.
State whether \( y \) is inversely proportional to \( x \) in the equation \( y = \frac{6}{x} \).
Given that \( y \propto \frac{1}{x} \) and \( y = 4 \) when \( x = 3 \), find \( y \) when \( x = 6 \).
Given that \( y \) is inversely proportional to \( x \), and \( y = 10 \) when \( x = 2 \), find the constant of proportionality.
The time taken to complete a journey is inversely proportional to the speed. If a journey takes 5 hours at 60 km/h, how long will it take at 100 km/h?
Write the relationship \( y \propto \frac{1}{x} \) as an equation using a constant of proportionality.
AQA
Exam-style questions based on the AQA GCSE Mathematics specification, focusing on forming and solving equations involving inverse proportion.
Given that \( y \propto \frac{1}{x} \) and \( y = 8 \) when \( x = 5 \), find an equation connecting \( y \) and \( x \).
If \( y \) is inversely proportional to \( x \), and \( y = 12 \) when \( x = 4 \), find \( x \) when \( y = 3 \).
The number of workers needed to complete a job is inversely proportional to the time taken. If 6 workers take 10 days, how many workers are required to complete the job in 4 days?
The pressure of a gas varies inversely with its volume. If the pressure is 200 kPa when the volume is 5 m^3, find the pressure when the volume is 8 m^3.
Explain how you recognise an inverse proportion from a table or graph.
OCR
Exam-style questions aligned with OCR GCSE Mathematics, emphasising reasoning, algebraic modelling, and graphical interpretation.
Given that \( y \propto \frac{1}{x} \), and \( y = 9 \) when \( x = 2 \), find the value of \( y \) when \( x = 6 \).
Write \( y \propto \frac{1}{x} \) as an equation involving a constant \( k \).
A fixed distance is travelled at different speeds. If it takes 3 hours at 80 km/h, how long will it take at 120 km/h?
Two variables are inversely proportional. When \( x = 4 \), \( y = 15 \). Find the value of \( y \) when \( x = 10 \).
State the key features of a graph that represents inverse proportion.
Exam Checklist
Step 1
If you see “inversely proportional”, write \( y = \frac{k}{x} \).
Step 2
Use known values to find \( k \) by multiplying.
Step 3
Substitute the new value into the completed equation.
Step 4
Check whether the answer makes sense: bigger \( x \), smaller \( y \).
Most common exam mistakes
Wrong formula
Using \( y = kx \) instead of \( y = \frac{k}{x} \).
Wrong constant
Dividing to find \( k \) when you should multiply.
Pattern confusion
Not checking whether the product stays constant.
Reasonableness mistake
Getting a larger answer when the question should produce a smaller one.
Common Mistakes
These are common mistakes students make when working with inverse proportion in GCSE Maths.
Using the wrong formula
A student uses \(y = kx\) instead of \(y = \frac{k}{x}\).
Inverse proportion follows \(y = \frac{k}{x}\) or \(xy = k\). This is different from direct proportion, which uses \(y = kx\).
Finding k incorrectly
A student divides instead of multiplying to find k.
For inverse proportion, use \(k = x \times y\), not division. Multiply the values to find the constant.
Relying only on “one goes up, one goes down”
A student assumes inverse proportion just because one value increases and the other decreases.
Check that the product \(xy\) is constant. This confirms inverse proportion.
Confusing direct and inverse proportion
A student uses the method for direct proportion.
Direct proportion uses \(y = kx\), while inverse proportion uses \(y = \frac{k}{x}\). Always identify the relationship first.
Expecting a straight-line graph
A student draws a straight line graph.
Inverse proportion graphs are curves (hyperbolas), not straight lines. They approach the axes but do not touch them.
Try It Yourself
Practise solving problems involving inverse proportional relationships.
Foundation Practice
Understand inverse proportion and solve simple problems.
4 workers take 12 hours to complete a job. How long would 2 workers take?
6 machines take 10 hours. How long do 3 machines take?
If speed doubles, what happens to time taken for a fixed journey? (Give answer as 'halves' or 'doubles')
Which situation shows inverse proportion?
8 workers take 6 hours. How long do 4 workers take?
A student says: 'If x doubles, y doubles in inverse proportion.' What is wrong?
10 workers take 4 hours. How long do 5 workers take?
If x increases, what happens to y in inverse proportion?
3 taps fill a tank in 9 hours. How long do 9 taps take?
Higher Practice
Solve inverse proportion problems using equations and constant k.
y is inversely proportional to x. When x = 2, y = 12. Find y when x = 6.
y ∝ 1/x. When x = 4, y = 10. Find y when x = 5.
y ∝ 1/x. If y = 6 when x = 3, what is k?
y ∝ 1/x. When x = 8, y = 3. Find y when x = 2.
Which equation represents inverse proportion?
y ∝ 1/x. When x = 10, y = 2. Find x when y = 5.
A student says y = 1/x + 3 is inverse proportion. Why is this wrong?
y ∝ 1/x. When x = 5, y = 6. Find y when x = 15.
If x is multiplied by 4, what happens to y in inverse proportion?
y ∝ 1/x. When x = 12, y = 5. Find x when y = 20.
Games
Practise this topic with interactive games.